From rickyyao at gmail.com Wed Apr 21 08:15:47 2021
From: rickyyao at gmail.com (Richard Yao)
Date: Wed, 21 Apr 2021 10:15:47 +1200
Subject: [Limdep Nlogit List] Conditional (posterior) class probabilities
for panel ordered latent class model
Message-ID:
Dear Everyone,
Greetings from New Zealand!
I am currently running panel ordered latent logit class models on NLOGIT 6
and would like to calculate the conditional (posterior) class
probabilities.
I have used the NLOGIT code below and was able to estimate the panel latent
class model but unfortunately, I could not find the conditional (posterior)
class probabilities in the "CLASSP_I" MATRIX.
I would highly appreciate any thoughts/advice.
Best wishes,
Richard Yao, PhD
SCION, Private Bag 3020
Rotorua 3046, New Zealand
P: 64 7 343 5747; M: 64 21 0247 3234
SAMPLE ; All$
SETPANEL ; Group = pid ; Pds = csnum $
OLOGIT
; Lhs = rank_inv
; Rhs = one, broad_ar, targ_ar, targ_grd, remo_inf, ster_ins, effect
; list
; Partial effects $
OLOGIT
; Lhs = rank_inv
; Rhs = one, broad_ar, targ_ar, targ_grd, remo_inf, ster_ins, effect
; Partial effects
; LCM
; Pts = 3
; Parameters (Save posterior results)
; Panel $
|-> OLOGIT
; Lhs = rank_inv
; Rhs = one, broad_ar, targ_ar, targ_grd, remo_inf, ster_ins, effect
; Partial effects
; LCM
; Pts = 3
; Parameters (Save posterior results)
; List
; Panel $
Line search at iteration 68 does not improve the function
Exiting optimization
-----------------------------------------------------------------------------
Latent Class / Panel OrdProbs Model
Dependent variable RANK_INV
Log likelihood function -77528.46129
Estimation based on N = 63984, K = 35
Inf.Cr.AIC = 155126.9 AIC/N = 2.424
Unbalanced panel has 1333 individuals
Latent class model with 3 latent classes
Ordered probability model
Ordered LOGIT probability model
LHS variable = values 0,1,..., 5
--------+--------------------------------------------------------------------
| Standard Prob. 95% Confidence
RANK_INV| Coefficient Error z |z|>Z* Interval
--------+--------------------------------------------------------------------
|Model parameters for latent class 1.............................
Constant| -3.52320*** .23606 -14.93 .0000 -3.98586 -3.06053
BROAD_AR| 5.95097*** .12678 46.94 .0000 5.70248 6.19946
TARG_AR| 6.92984*** .11222 61.75 .0000 6.70989 7.14979
TARG_GRD| 7.33345*** .10946 67.00 .0000 7.11891 7.54799
REMO_INF| 6.63923*** .11302 58.74 .0000 6.41772 6.86075
STER_INS| 6.33949*** .12028 52.71 .0000 6.10375 6.57523
EFFECT| 5.53569*** .09779 56.61 .0000 5.34403 5.72734
Mu(01)| 3.99266*** .23141 17.25 .0000 3.53910 4.44622
Mu(02)| 5.43495*** .17091 31.80 .0000 5.09997 5.76994
Mu(03)| 6.73958*** .20804 32.40 .0000 6.33183 7.14734
Mu(04)| 8.21072*** .21450 38.28 .0000 7.79031 8.63114
|Model parameters for latent class 2.............................
Constant| -2.52192*** .29340 -8.60 .0000 -3.09697 -1.94688
BROAD_AR| 3.26588*** .08805 37.09 .0000 3.09332 3.43845
TARG_AR| 7.12458*** .10202 69.84 .0000 6.92463 7.32453
TARG_GRD| 8.48640*** .09783 86.74 .0000 8.29465 8.67815
REMO_INF| 8.53274*** .09303 91.72 .0000 8.35039 8.71508
STER_INS| 8.39927*** .09673 86.83 .0000 8.20968 8.58886
EFFECT| 4.11553*** .10494 39.22 .0000 3.90985 4.32122
Mu(01)| 4.38768*** .31560 13.90 .0000 3.76912 5.00624
Mu(02)| 6.49755*** .24170 26.88 .0000 6.02382 6.97128
Mu(03)| 7.90108*** .28617 27.61 .0000 7.34020 8.46195
Mu(04)| 9.34575*** .33196 28.15 .0000 8.69512 9.99638
|Model parameters for latent class 3.............................
Constant| 1.08374*** .33059 3.28 .0010 .43581 1.73168
BROAD_AR| -1.86830*** .06969 -26.81 .0000 -2.00489 -1.73171
TARG_AR| .13114** .06415 2.04 .0409 .00541 .25687
TARG_GRD| 1.16636*** .06240 18.69 .0000 1.04407 1.28866
REMO_INF| 1.81549*** .06787 26.75 .0000 1.68247 1.94851
STER_INS| 1.05045*** .05081 20.67 .0000 .95086 1.15005
EFFECT| 1.41528*** .08621 16.42 .0000 1.24631 1.58425
Mu(01)| 1.24356*** .38216 3.25 .0011 .49453 1.99259
Mu(02)| 2.20918*** .18116 12.19 .0000 1.85412 2.56424
Mu(03)| 3.12403*** .38240 8.17 .0000 2.37453 3.87352
Mu(04)| 4.21616*** .39565 10.66 .0000 3.44069 4.99163
|Estimated prior probabilities for class membership..............
Class1Pr| .61720*** .01381 44.68 .0000 .59012 .64427
Class2Pr| .22585*** .01209 18.67 .0000 .20214 .24955
Class3Pr| .15696*** .01012 15.51 .0000 .13713 .17679
--------+--------------------------------------------------------------------
***, **, * ==> Significance at 1%, 5%, 10% level.
Model was estimated on Apr 21, 2021 at 10:07:48 AM
-----------------------------------------------------------------------------
RP cannot compute ME for ORDERED when J > 9..
From Thao.T.Thai at monash.edu Wed Apr 21 16:47:30 2021
From: Thao.T.Thai at monash.edu (Thao Thai)
Date: Wed, 21 Apr 2021 16:47:30 +1000
Subject: [Limdep Nlogit List] Question about Convolution test
Message-ID:
Hi Nlogit user community,
I would like to compare the WTP estimates from two WTP-space models (all
random coefficients) using two different datasets. I am wondering what is
the detailed procedure to conduct a Convolution test (Poe test) on the
distributions of WTPs estimates in Nlogit?
I could not find the procedure in the Manual, so any suggestions would be
appreciated.
Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for
measuring the difference of empirical distributions. American Journal of
Agricultural Economics, 87, 353?365.
Thank you in advance.
Best wishes,
Thao
From Thao.T.Thai at monash.edu Thu Apr 22 15:41:29 2021
From: Thao.T.Thai at monash.edu (Thao Thai)
Date: Thu, 22 Apr 2021 15:41:29 +1000
Subject: [Limdep Nlogit List] Fwd: Question about Convolution test
In-Reply-To:
References:
Message-ID:
Hi again,
I found one relevant previous message with instructions on the Poe test
below (
https://protect-au.mimecast.com/s/cs-gCVARKgCxg9OXRfGUCf7?domain=mailman.sydney.edu.au.
However, I am still not sure how to test WTP estimates from WTP-space
models for individual attributes from two datasets.
I tried to replicate the suggested command as below:
1. I ran the first WTP-space model on one data subset and defined the
vector of WTP estimates of 12 attributes:
MATRIX ; vector1 = b (6:20)$
2. I ran the second WTP-space using another data subset and defined the
vector of WTP estimates (two data subsets have information on the same
attributes)
MATRIX ; vector2 = b (6:20)$
3. I then ran the Poe test command as instructed.
CALC ; List ; Poe(vector1,vector2,1) $
This command produced one single test statistic. However, I would like to
have Poe test statistics for 12 individual attributes.
Your suggestions would be appreciated. Please help!
Best wishes,
Thao
"CALC ; List ; Poe(vector1,vector2) $
This produces the statistic based on the full convolution. Vectors must be
defined
with a MATRIX command. If x1 and x2 are two variables, use
MATRIX ; vector1 = x1 ; vector2 = x2 $
then CALC Poe. The test can be based on the difference of the vectors if
they
are the same length. Use
CALC ; List ; Poe(vector1,vector2,1) $
Regards
Bill Greene"
---------- Forwarded message ---------
From: Thao Thai
Date: Wed, 21 Apr 2021 at 16:47
Subject: Question about Convolution test
To: Limdep and Nlogit Mailing List
Hi Nlogit user community,
I would like to compare the WTP estimates from two WTP-space models (all
random coefficients) using two different datasets. I am wondering what is
the detailed procedure to conduct a Convolution test (Poe test) on the
distributions of WTPs estimates in Nlogit?
I could not find the procedure in the Manual, so any suggestions would be
appreciated.
Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for
measuring the difference of empirical distributions. American Journal of
Agricultural Economics, 87, 353?365.
Thank you in advance.
Best wishes,
Thao
From michael.danne at agr.uni-goettingen.de Thu Apr 22 15:54:04 2021
From: michael.danne at agr.uni-goettingen.de (Danne, Michael)
Date: Thu, 22 Apr 2021 05:54:04 +0000
Subject: [Limdep Nlogit List] Fwd: Question about Convolution test
In-Reply-To:
References:
Message-ID: <3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de>
Hi Thao,
Run the model for the first subset with including the ;parameter command. Than you can copy/paste the individual WTPs in Excel. Do it in the same way with the second subset. In your Excel, each attribute is in a single column. Attribute 1 of subset one and attribute one of subset 2 should have different names in excel, for example car1 and car2. If you than use the poe test it is than CALC ; List ; Poe(car1,car2,1) $
You have to be careful which vector you list first in the command. As I remember the higher vector (higher mean) has to be the first.
I don?t know if there is an easier way, but it should work.
Best regards
Michael
-----Urspr?ngliche Nachricht-----
Von: Limdep Im Auftrag von Thao Thai via Limdep
Gesendet: Donnerstag, 22. April 2021 07:41
An: Limdep and Nlogit Mailing List
Cc: Thao Thai
Betreff: [Limdep Nlogit List] Fwd: Question about Convolution test
Hi again,
I found one relevant previous message with instructions on the Poe test below ( https://protect-au.mimecast.com/s/zJhzCL7EwMfRQ4KpNIB1znL?domain=mailman.sydney.edu.au).
However, I am still not sure how to test WTP estimates from WTP-space models for individual attributes from two datasets.
I tried to replicate the suggested command as below:
1. I ran the first WTP-space model on one data subset and defined the vector of WTP estimates of 12 attributes:
MATRIX ; vector1 = b (6:20)$
2. I ran the second WTP-space using another data subset and defined the vector of WTP estimates (two data subsets have information on the same
attributes)
MATRIX ; vector2 = b (6:20)$
3. I then ran the Poe test command as instructed.
CALC ; List ; Poe(vector1,vector2,1) $
This command produced one single test statistic. However, I would like to have Poe test statistics for 12 individual attributes.
Your suggestions would be appreciated. Please help!
Best wishes,
Thao
"CALC ; List ; Poe(vector1,vector2) $
This produces the statistic based on the full convolution. Vectors must be defined with a MATRIX command. If x1 and x2 are two variables, use MATRIX ; vector1 = x1 ; vector2 = x2 $ then CALC Poe. The test can be based on the difference of the vectors if they are the same length. Use CALC ; List ; Poe(vector1,vector2,1) $ Regards Bill Greene"
---------- Forwarded message ---------
From: Thao Thai
Date: Wed, 21 Apr 2021 at 16:47
Subject: Question about Convolution test
To: Limdep and Nlogit Mailing List
Hi Nlogit user community,
I would like to compare the WTP estimates from two WTP-space models (all random coefficients) using two different datasets. I am wondering what is the detailed procedure to conduct a Convolution test (Poe test) on the distributions of WTPs estimates in Nlogit?
I could not find the procedure in the Manual, so any suggestions would be appreciated.
Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for measuring the difference of empirical distributions. American Journal of Agricultural Economics, 87, 353?365.
Thank you in advance.
Best wishes,
Thao
_______________________________________________
Limdep site list
Limdep at mailman.sydney.edu.au
https://protect-au.mimecast.com/s/ZWd9CMwGxOtqzWX0xskoD9k?domain=limdep.itls.usyd.edu.au
From Thao.T.Thai at monash.edu Thu Apr 22 16:39:45 2021
From: Thao.T.Thai at monash.edu (Thao Thai)
Date: Thu, 22 Apr 2021 16:39:45 +1000
Subject: [Limdep Nlogit List] Fwd: Fwd: Question about Convolution test
In-Reply-To: <3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de>
References:
<3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de>
Message-ID:
Hi Michael,
Thank you so much for your help! It works wonderfully.
But .. I have another question. How can I calculate the critical values for
the Poe test? Are there a table of critical values available to compare the
test statistics with?
Your help is much appreciated!
Best wishes,
Thao
---------- Forwarded message ---------
From: Danne, Michael
Date: Thu, 22 Apr 2021 at 15:54
Subject: AW: [Limdep Nlogit List] Fwd: Question about Convolution test
To: Limdep and Nlogit Mailing List
Cc: Thao Thai
Hi Thao,
Run the model for the first subset with including the ;parameter command.
Than you can copy/paste the individual WTPs in Excel. Do it in the same way
with the second subset. In your Excel, each attribute is in a single
column. Attribute 1 of subset one and attribute one of subset 2 should have
different names in excel, for example car1 and car2. If you than use the
poe test it is than CALC ; List ; Poe(car1,car2,1) $
You have to be careful which vector you list first in the command. As I
remember the higher vector (higher mean) has to be the first.
I don?t know if there is an easier way, but it should work.
Best regards
Michael
-----Urspr?ngliche Nachricht-----
Von: Limdep Im Auftrag von Thao Thai
via Limdep
Gesendet: Donnerstag, 22. April 2021 07:41
An: Limdep and Nlogit Mailing List
Cc: Thao Thai
Betreff: [Limdep Nlogit List] Fwd: Question about Convolution test
Hi again,
I found one relevant previous message with instructions on the Poe test
below (
https://protect-au.mimecast.com/s/FNoMCoV1kpfrvZ33li1HGqD?domain=mailman.sydney.edu.au.
However, I am still not sure how to test WTP estimates from WTP-space
models for individual attributes from two datasets.
I tried to replicate the suggested command as below:
1. I ran the first WTP-space model on one data subset and defined the
vector of WTP estimates of 12 attributes:
MATRIX ; vector1 = b (6:20)$
2. I ran the second WTP-space using another data subset and defined the
vector of WTP estimates (two data subsets have information on the same
attributes)
MATRIX ; vector2 = b (6:20)$
3. I then ran the Poe test command as instructed.
CALC ; List ; Poe(vector1,vector2,1) $
This command produced one single test statistic. However, I would like to
have Poe test statistics for 12 individual attributes.
Your suggestions would be appreciated. Please help!
Best wishes,
Thao
"CALC ; List ; Poe(vector1,vector2) $
This produces the statistic based on the full convolution. Vectors must be
defined with a MATRIX command. If x1 and x2 are two variables, use MATRIX
; vector1 = x1 ; vector2 = x2 $ then CALC Poe. The test can be based on
the difference of the vectors if they are the same length. Use CALC ; List
; Poe(vector1,vector2,1) $ Regards Bill Greene"
---------- Forwarded message ---------
From: Thao Thai
Date: Wed, 21 Apr 2021 at 16:47
Subject: Question about Convolution test
To: Limdep and Nlogit Mailing List
Hi Nlogit user community,
I would like to compare the WTP estimates from two WTP-space models (all
random coefficients) using two different datasets. I am wondering what is
the detailed procedure to conduct a Convolution test (Poe test) on the
distributions of WTPs estimates in Nlogit?
I could not find the procedure in the Manual, so any suggestions would be
appreciated.
Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for
measuring the difference of empirical distributions. American Journal of
Agricultural Economics, 87, 353?365.
Thank you in advance.
Best wishes,
Thao
_______________________________________________
Limdep site list
Limdep at mailman.sydney.edu.au
https://protect-au.mimecast.com/s/II58Cp81lrtnAK33QTDu1K4?domain=limdep.itls.usyd.edu.au
From Thao.T.Thai at monash.edu Thu Apr 22 23:13:28 2021
From: Thao.T.Thai at monash.edu (Thao Thai)
Date: Thu, 22 Apr 2021 23:13:28 +1000
Subject: [Limdep Nlogit List] Fwd: Question about Convolution test
In-Reply-To: <3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de>
References:
<3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de>
Message-ID:
Hi Nlogit users,
Following Michael's instructions, I am able to generate Poe test statistics
for individual attributes as below
|-> CALC ;List; Poe(PRLH2,FRLH2,1) $
[CALC] = 264.1756004
|-> CALC ;List; Poe(PFL,FFL,1) $
[CALC] = 223.8058368
|-> CALC ;List; Poe(PCR1,FCR1,1) $
[CALC] = 1079.2828222
|-> CALC ;List; Poe(PCR2,FCR2,1) $
[CALC] = 135.7597390
|-> CALC ;List; Poe(PLO1,FLO1,1) $
[CALC] = 3489.5048159
|-> CALC ;List; Poe(PRLC1,FRLC1,1) $
[CALC] = 235.9289009
|-> CALC ;List; Poe(PRLC2,FRLC2,1) $
[CALC] = 522.8063550
Please let me know if these huge figures look sensible in nlogit and how to
obtain p-values or level of significance for these figures? Please help or
point me to the available instructions. Please help!
Thank you in advance.
Best regards,
Thao
On Thu, 22 Apr 2021 at 15:54, Danne, Michael <
michael.danne at agr.uni-goettingen.de> wrote:
> Hi Thao,
>
> Run the model for the first subset with including the ;parameter command.
> Than you can copy/paste the individual WTPs in Excel. Do it in the same way
> with the second subset. In your Excel, each attribute is in a single
> column. Attribute 1 of subset one and attribute one of subset 2 should have
> different names in excel, for example car1 and car2. If you than use the
> poe test it is than CALC ; List ; Poe(car1,car2,1) $
> You have to be careful which vector you list first in the command. As I
> remember the higher vector (higher mean) has to be the first.
>
> I don?t know if there is an easier way, but it should work.
>
> Best regards
> Michael
>
> -----Urspr?ngliche Nachricht-----
> Von: Limdep Im Auftrag von Thao
> Thai via Limdep
> Gesendet: Donnerstag, 22. April 2021 07:41
> An: Limdep and Nlogit Mailing List
> Cc: Thao Thai
> Betreff: [Limdep Nlogit List] Fwd: Question about Convolution test
>
> Hi again,
>
> I found one relevant previous message with instructions on the Poe test
> below (
> https://protect-au.mimecast.com/s/8VIQC91WPRTk21ABziopbLO?domain=mailman.sydney.edu.au).
> However, I am still not sure how to test WTP estimates from WTP-space
> models for individual attributes from two datasets.
>
> I tried to replicate the suggested command as below:
> 1. I ran the first WTP-space model on one data subset and defined the
> vector of WTP estimates of 12 attributes:
> MATRIX ; vector1 = b (6:20)$
>
> 2. I ran the second WTP-space using another data subset and defined the
> vector of WTP estimates (two data subsets have information on the same
> attributes)
> MATRIX ; vector2 = b (6:20)$
>
> 3. I then ran the Poe test command as instructed.
> CALC ; List ; Poe(vector1,vector2,1) $
> This command produced one single test statistic. However, I would like to
> have Poe test statistics for 12 individual attributes.
>
> Your suggestions would be appreciated. Please help!
> Best wishes,
> Thao
>
>
> "CALC ; List ; Poe(vector1,vector2) $
> This produces the statistic based on the full convolution. Vectors must be
> defined with a MATRIX command. If x1 and x2 are two variables, use MATRIX
> ; vector1 = x1 ; vector2 = x2 $ then CALC Poe. The test can be based on
> the difference of the vectors if they are the same length. Use CALC ; List
> ; Poe(vector1,vector2,1) $ Regards Bill Greene"
>
>
> ---------- Forwarded message ---------
> From: Thao Thai
> Date: Wed, 21 Apr 2021 at 16:47
> Subject: Question about Convolution test
> To: Limdep and Nlogit Mailing List
>
>
> Hi Nlogit user community,
>
> I would like to compare the WTP estimates from two WTP-space models (all
> random coefficients) using two different datasets. I am wondering what is
> the detailed procedure to conduct a Convolution test (Poe test) on the
> distributions of WTPs estimates in Nlogit?
>
> I could not find the procedure in the Manual, so any suggestions would be
> appreciated.
>
> Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for
> measuring the difference of empirical distributions. American Journal of
> Agricultural Economics, 87, 353?365.
>
> Thank you in advance.
> Best wishes,
> Thao
> _______________________________________________
> Limdep site list
> Limdep at mailman.sydney.edu.au
> https://protect-au.mimecast.com/s/O2wyC0YKPviGm8Q3kfD00Yy?domain=limdep.itls.usyd.edu.au
>
>
From Thao.T.Thai at monash.edu Mon Apr 26 15:20:54 2021
From: Thao.T.Thai at monash.edu (Thao Thai)
Date: Mon, 26 Apr 2021 15:20:54 +1000
Subject: [Limdep Nlogit List] WTP- space model: Confidence interval of WTP
distribution using Delta method
Message-ID:
Dear Nlogit users,
Please help if you can! Your help is much appreciated!
I ran a WTP-space model of which the results are below. Please help me
clarify some of my confusions:
(1) Is the confidence interval of the random parameters reported in the
model output, for example of the HOS variable, the confidence interval of
the mean WTP estimate for HOS variable?
(2) Does that mean the WTP distribution for HOS variable depends on the *mean
*WTP and its *standard error *(i.e. confidence interval of the mean WTP)
and the *standard deviation* (i.e. the estimated coefficients and standard
error for NsHOS) of the distribution for the WTP of HOS variables?
Please help:
(3) How can I compute the confidence intervals of WTPs distribution using
Delta method?
(4) How can I compute the confidence interval of the mean WTP using Delta
method? Is it the confidence interval reported in the WTP-space model
output?
Suppose the Delta method Wald syntax is
*Wald; Parameters = b; Covariance = varb*
*;Labels = hos, pri, ind, gov, non, rlh1, rlh2, fl, cr1, cr2, lo1, sa,
rlc1, rlc2, lo2, rlp1, rli1, rli2, rlg1, rln1;Fn1 = ? ;Fn2 = ?*
*$*
I got confused about what to put in the function to get confidence
intervals of WTPs where the coefficients are already WTPs values?
I really look forward to your answers! Thank you in advance!
Best regards,
Thao
-----------------------------------------------------------------------------
Generalized Mixed (RP) Logit Model
Dependent variable CHO
Log likelihood function -6513.18857
Restricted log likelihood -12150.65191
Chi squared [ 39](P= .000) 11274.92669
Significance level .00000
McFadden Pseudo R-squared .4639639
Estimation based on N = 5530, K = 39
Inf.Cr.AIC = 13104.4 AIC/N = 2.370
---------------------------------------
Log likelihood R-sqrd R2Adj
No coefficients ********** .4640 .4628
Constants only can be computed directly
Use NLOGIT ;...;RHS=ONE$
At start values -7718.0848 .1561 .1543
Note: R-sqrd = 1 - logL/Logl(constants)
Warning: Model does not contain a full
set of ASCs. R-sqrd is problematic. Use
model setup with ;RHS=one to get LogL0.
---------------------------------------
Response data are given as ind. choices
Replications for simulated probs. = 50
Used Halton sequences in simulations.
RPL model with panel has 790 groups
Fixed number of obsrvs./group= 7
BHHH estimator used for asymp. variance
Number of obs.= 5530, skipped 0 obs
--------+--------------------------------------------------------------------
| Standard Prob. 95% Confidence
CHO| Coefficient Error z |z|>Z* Interval
--------+--------------------------------------------------------------------
|Random parameters in utility
functions..............................
HOS| 5.92660 8.03544 .74 .4608 -9.82257 21.67578
PRI| 30.0879*** 6.82100 4.41 .0000 16.7190 43.4568
IND| -74.2164*** 8.56240 -8.67 .0000 -90.9984 -57.4344
GOV| -1.41410 7.62304 -.19 .8528 -16.35499 13.52679
NON| -.55721 7.71549 -.07 .9424 -15.67928 14.56486
RLH1| -4.88831 9.96395 -.49 .6237 -24.41730 14.64068
RLH2| 15.4004** 7.46852 2.06 .0392 .7624 30.0385
FL| 15.1360*** 3.00154 5.04 .0000 9.2531 21.0189
CR1| 33.4554*** 3.29616 10.15 .0000 26.9950 39.9158
CR2| 17.2478*** 4.98946 3.46 .0005 7.4687 27.0270
LO1| -56.0650*** 3.79442 -14.78 .0000 -63.5019 -48.6280
SA| 1.0 .....(Fixed Parameter).....
RLC1| 11.6994 9.01142 1.30 .1942 -5.9627 29.3614
RLC2| 21.9054** 8.76364 2.50 .0124 4.7290 39.0818
LO2| -76.1803*** 5.08817 -14.97 .0000 -86.1529 -66.2077
RLP1| -21.7674*** 6.31574 -3.45 .0006 -34.1460 -9.3887
RLI1| 36.7621*** 9.08386 4.05 .0001 18.9581 54.5662
RLI2| 48.4521*** 6.98327 6.94 .0000 34.7651 62.1390
RLG1| -15.8780** 6.61678 -2.40 .0164 -28.8467 -2.9094
RLN1| -32.0373*** 8.21917 -3.90 .0001 -48.1465 -15.9280
|Distns. of RPs. Std.Devs or limits of
triangular....................
NsHOS| 61.2749*** 5.69437 10.76 .0000 50.1141 72.4356
NsPRI| 52.0645*** 5.48074 9.50 .0000 41.3224 62.8065
NsIND| 81.7682*** 6.32951 12.92 .0000 69.3626 94.1738
NsGOV| 70.6895*** 5.40187 13.09 .0000 60.1021 81.2770
NsNON| 58.2880*** 6.73963 8.65 .0000 45.0786 71.4975
NsRLH1| 38.4853** 16.01183 2.40 .0162 7.1027 69.8679
NsRLH2| 15.0987 14.26854 1.06 .2900 -12.8671 43.0645
NsFL| 27.3007*** 5.52125 4.94 .0000 16.4792 38.1221
NsCR1| 1.25925 7.01920 .18 .8576 -12.49812 15.01662
NsCR2| 9.06253 9.13084 .99 .3209 -8.83358 26.95864
NsLO1| 58.1808*** 4.70198 12.37 .0000 48.9651 67.3965
CsSA| 0.0 .....(Fixed Parameter).....
NsRLC1| 61.6887*** 9.56351 6.45 .0000 42.9445 80.4328
NsRLC2| 8.02381 13.69708 .59 .5580 -18.82197 34.86959
NsLO2| 33.7236*** 7.81182 4.32 .0000 18.4128 49.0345
NsRLP1| 3.64345 12.20383 .30 .7653 -20.27562 27.56251
NsRLI1| 52.0114*** 13.12794 3.96 .0001 26.2811 77.7417
NsRLI2| 7.20127 13.87235 .52 .6037 -19.98804 34.39057
NsRLG1| 14.7726 11.03772 1.34 .1808 -6.8609 36.4061
NsRLN1| 51.6333*** 9.86131 5.24 .0000 32.3055 70.9611
|Variance parameter tau in GMX scale
parameter.......................
TauScale| 0.0 .....(Fixed Parameter).....
|Weighting parameter gamma in GMX
model..............................
GammaMXL| 0.0 .....(Fixed Parameter).....
|Coefficient on SA in preference space
form....................
Beta0WTP| .01539*** .00043 35.64 .0000 .01454 .01623
S_b0_WTP| 0.0 .....(Fixed Parameter).....
| Sample Mean Sample
Std.Dev.....................................
Sigma(i)| 1.0*** .1322D-05 ******** .0000 .10000D+01 .10000D+01
--------+--------------------------------------------------------------------
nnnnn.D-xx or D+xx => multiply by 10 to -xx or +xx.
***, **, * ==> Significance at 1%, 5%, 10% level.
Fixed parameter ... is constrained to equal the value or
had a nonpositive st.error because of an earlier problem.
Model was estimated on Apr 23, 2021 at 08:10:02 PM
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