From rickyyao at gmail.com Wed Apr 21 08:15:47 2021 From: rickyyao at gmail.com (Richard Yao) Date: Wed, 21 Apr 2021 10:15:47 +1200 Subject: [Limdep Nlogit List] Conditional (posterior) class probabilities for panel ordered latent class model Message-ID: Dear Everyone, Greetings from New Zealand! I am currently running panel ordered latent logit class models on NLOGIT 6 and would like to calculate the conditional (posterior) class probabilities. I have used the NLOGIT code below and was able to estimate the panel latent class model but unfortunately, I could not find the conditional (posterior) class probabilities in the "CLASSP_I" MATRIX. I would highly appreciate any thoughts/advice. Best wishes, Richard Yao, PhD SCION, Private Bag 3020 Rotorua 3046, New Zealand P: 64 7 343 5747; M: 64 21 0247 3234 SAMPLE ; All$ SETPANEL ; Group = pid ; Pds = csnum $ OLOGIT ; Lhs = rank_inv ; Rhs = one, broad_ar, targ_ar, targ_grd, remo_inf, ster_ins, effect ; list ; Partial effects $ OLOGIT ; Lhs = rank_inv ; Rhs = one, broad_ar, targ_ar, targ_grd, remo_inf, ster_ins, effect ; Partial effects ; LCM ; Pts = 3 ; Parameters (Save posterior results) ; Panel $ |-> OLOGIT ; Lhs = rank_inv ; Rhs = one, broad_ar, targ_ar, targ_grd, remo_inf, ster_ins, effect ; Partial effects ; LCM ; Pts = 3 ; Parameters (Save posterior results) ; List ; Panel $ Line search at iteration 68 does not improve the function Exiting optimization ----------------------------------------------------------------------------- Latent Class / Panel OrdProbs Model Dependent variable RANK_INV Log likelihood function -77528.46129 Estimation based on N = 63984, K = 35 Inf.Cr.AIC = 155126.9 AIC/N = 2.424 Unbalanced panel has 1333 individuals Latent class model with 3 latent classes Ordered probability model Ordered LOGIT probability model LHS variable = values 0,1,..., 5 --------+-------------------------------------------------------------------- | Standard Prob. 95% Confidence RANK_INV| Coefficient Error z |z|>Z* Interval --------+-------------------------------------------------------------------- |Model parameters for latent class 1............................. Constant| -3.52320*** .23606 -14.93 .0000 -3.98586 -3.06053 BROAD_AR| 5.95097*** .12678 46.94 .0000 5.70248 6.19946 TARG_AR| 6.92984*** .11222 61.75 .0000 6.70989 7.14979 TARG_GRD| 7.33345*** .10946 67.00 .0000 7.11891 7.54799 REMO_INF| 6.63923*** .11302 58.74 .0000 6.41772 6.86075 STER_INS| 6.33949*** .12028 52.71 .0000 6.10375 6.57523 EFFECT| 5.53569*** .09779 56.61 .0000 5.34403 5.72734 Mu(01)| 3.99266*** .23141 17.25 .0000 3.53910 4.44622 Mu(02)| 5.43495*** .17091 31.80 .0000 5.09997 5.76994 Mu(03)| 6.73958*** .20804 32.40 .0000 6.33183 7.14734 Mu(04)| 8.21072*** .21450 38.28 .0000 7.79031 8.63114 |Model parameters for latent class 2............................. Constant| -2.52192*** .29340 -8.60 .0000 -3.09697 -1.94688 BROAD_AR| 3.26588*** .08805 37.09 .0000 3.09332 3.43845 TARG_AR| 7.12458*** .10202 69.84 .0000 6.92463 7.32453 TARG_GRD| 8.48640*** .09783 86.74 .0000 8.29465 8.67815 REMO_INF| 8.53274*** .09303 91.72 .0000 8.35039 8.71508 STER_INS| 8.39927*** .09673 86.83 .0000 8.20968 8.58886 EFFECT| 4.11553*** .10494 39.22 .0000 3.90985 4.32122 Mu(01)| 4.38768*** .31560 13.90 .0000 3.76912 5.00624 Mu(02)| 6.49755*** .24170 26.88 .0000 6.02382 6.97128 Mu(03)| 7.90108*** .28617 27.61 .0000 7.34020 8.46195 Mu(04)| 9.34575*** .33196 28.15 .0000 8.69512 9.99638 |Model parameters for latent class 3............................. Constant| 1.08374*** .33059 3.28 .0010 .43581 1.73168 BROAD_AR| -1.86830*** .06969 -26.81 .0000 -2.00489 -1.73171 TARG_AR| .13114** .06415 2.04 .0409 .00541 .25687 TARG_GRD| 1.16636*** .06240 18.69 .0000 1.04407 1.28866 REMO_INF| 1.81549*** .06787 26.75 .0000 1.68247 1.94851 STER_INS| 1.05045*** .05081 20.67 .0000 .95086 1.15005 EFFECT| 1.41528*** .08621 16.42 .0000 1.24631 1.58425 Mu(01)| 1.24356*** .38216 3.25 .0011 .49453 1.99259 Mu(02)| 2.20918*** .18116 12.19 .0000 1.85412 2.56424 Mu(03)| 3.12403*** .38240 8.17 .0000 2.37453 3.87352 Mu(04)| 4.21616*** .39565 10.66 .0000 3.44069 4.99163 |Estimated prior probabilities for class membership.............. Class1Pr| .61720*** .01381 44.68 .0000 .59012 .64427 Class2Pr| .22585*** .01209 18.67 .0000 .20214 .24955 Class3Pr| .15696*** .01012 15.51 .0000 .13713 .17679 --------+-------------------------------------------------------------------- ***, **, * ==> Significance at 1%, 5%, 10% level. Model was estimated on Apr 21, 2021 at 10:07:48 AM ----------------------------------------------------------------------------- RP cannot compute ME for ORDERED when J > 9.. From Thao.T.Thai at monash.edu Wed Apr 21 16:47:30 2021 From: Thao.T.Thai at monash.edu (Thao Thai) Date: Wed, 21 Apr 2021 16:47:30 +1000 Subject: [Limdep Nlogit List] Question about Convolution test Message-ID: Hi Nlogit user community, I would like to compare the WTP estimates from two WTP-space models (all random coefficients) using two different datasets. I am wondering what is the detailed procedure to conduct a Convolution test (Poe test) on the distributions of WTPs estimates in Nlogit? I could not find the procedure in the Manual, so any suggestions would be appreciated. Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for measuring the difference of empirical distributions. American Journal of Agricultural Economics, 87, 353?365. Thank you in advance. Best wishes, Thao From Thao.T.Thai at monash.edu Thu Apr 22 15:41:29 2021 From: Thao.T.Thai at monash.edu (Thao Thai) Date: Thu, 22 Apr 2021 15:41:29 +1000 Subject: [Limdep Nlogit List] Fwd: Question about Convolution test In-Reply-To: References: Message-ID: Hi again, I found one relevant previous message with instructions on the Poe test below ( https://protect-au.mimecast.com/s/cs-gCVARKgCxg9OXRfGUCf7?domain=mailman.sydney.edu.au. However, I am still not sure how to test WTP estimates from WTP-space models for individual attributes from two datasets. I tried to replicate the suggested command as below: 1. I ran the first WTP-space model on one data subset and defined the vector of WTP estimates of 12 attributes: MATRIX ; vector1 = b (6:20)$ 2. I ran the second WTP-space using another data subset and defined the vector of WTP estimates (two data subsets have information on the same attributes) MATRIX ; vector2 = b (6:20)$ 3. I then ran the Poe test command as instructed. CALC ; List ; Poe(vector1,vector2,1) $ This command produced one single test statistic. However, I would like to have Poe test statistics for 12 individual attributes. Your suggestions would be appreciated. Please help! Best wishes, Thao "CALC ; List ; Poe(vector1,vector2) $ This produces the statistic based on the full convolution. Vectors must be defined with a MATRIX command. If x1 and x2 are two variables, use MATRIX ; vector1 = x1 ; vector2 = x2 $ then CALC Poe. The test can be based on the difference of the vectors if they are the same length. Use CALC ; List ; Poe(vector1,vector2,1) $ Regards Bill Greene" ---------- Forwarded message --------- From: Thao Thai Date: Wed, 21 Apr 2021 at 16:47 Subject: Question about Convolution test To: Limdep and Nlogit Mailing List Hi Nlogit user community, I would like to compare the WTP estimates from two WTP-space models (all random coefficients) using two different datasets. I am wondering what is the detailed procedure to conduct a Convolution test (Poe test) on the distributions of WTPs estimates in Nlogit? I could not find the procedure in the Manual, so any suggestions would be appreciated. Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for measuring the difference of empirical distributions. American Journal of Agricultural Economics, 87, 353?365. Thank you in advance. Best wishes, Thao From michael.danne at agr.uni-goettingen.de Thu Apr 22 15:54:04 2021 From: michael.danne at agr.uni-goettingen.de (Danne, Michael) Date: Thu, 22 Apr 2021 05:54:04 +0000 Subject: [Limdep Nlogit List] Fwd: Question about Convolution test In-Reply-To: References: Message-ID: <3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de> Hi Thao, Run the model for the first subset with including the ;parameter command. Than you can copy/paste the individual WTPs in Excel. Do it in the same way with the second subset. In your Excel, each attribute is in a single column. Attribute 1 of subset one and attribute one of subset 2 should have different names in excel, for example car1 and car2. If you than use the poe test it is than CALC ; List ; Poe(car1,car2,1) $ You have to be careful which vector you list first in the command. As I remember the higher vector (higher mean) has to be the first. I don?t know if there is an easier way, but it should work. Best regards Michael -----Urspr?ngliche Nachricht----- Von: Limdep Im Auftrag von Thao Thai via Limdep Gesendet: Donnerstag, 22. April 2021 07:41 An: Limdep and Nlogit Mailing List Cc: Thao Thai Betreff: [Limdep Nlogit List] Fwd: Question about Convolution test Hi again, I found one relevant previous message with instructions on the Poe test below ( https://protect-au.mimecast.com/s/zJhzCL7EwMfRQ4KpNIB1znL?domain=mailman.sydney.edu.au). However, I am still not sure how to test WTP estimates from WTP-space models for individual attributes from two datasets. I tried to replicate the suggested command as below: 1. I ran the first WTP-space model on one data subset and defined the vector of WTP estimates of 12 attributes: MATRIX ; vector1 = b (6:20)$ 2. I ran the second WTP-space using another data subset and defined the vector of WTP estimates (two data subsets have information on the same attributes) MATRIX ; vector2 = b (6:20)$ 3. I then ran the Poe test command as instructed. CALC ; List ; Poe(vector1,vector2,1) $ This command produced one single test statistic. However, I would like to have Poe test statistics for 12 individual attributes. Your suggestions would be appreciated. Please help! Best wishes, Thao "CALC ; List ; Poe(vector1,vector2) $ This produces the statistic based on the full convolution. Vectors must be defined with a MATRIX command. If x1 and x2 are two variables, use MATRIX ; vector1 = x1 ; vector2 = x2 $ then CALC Poe. The test can be based on the difference of the vectors if they are the same length. Use CALC ; List ; Poe(vector1,vector2,1) $ Regards Bill Greene" ---------- Forwarded message --------- From: Thao Thai Date: Wed, 21 Apr 2021 at 16:47 Subject: Question about Convolution test To: Limdep and Nlogit Mailing List Hi Nlogit user community, I would like to compare the WTP estimates from two WTP-space models (all random coefficients) using two different datasets. I am wondering what is the detailed procedure to conduct a Convolution test (Poe test) on the distributions of WTPs estimates in Nlogit? I could not find the procedure in the Manual, so any suggestions would be appreciated. Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for measuring the difference of empirical distributions. American Journal of Agricultural Economics, 87, 353?365. Thank you in advance. Best wishes, Thao _______________________________________________ Limdep site list Limdep at mailman.sydney.edu.au https://protect-au.mimecast.com/s/ZWd9CMwGxOtqzWX0xskoD9k?domain=limdep.itls.usyd.edu.au From Thao.T.Thai at monash.edu Thu Apr 22 16:39:45 2021 From: Thao.T.Thai at monash.edu (Thao Thai) Date: Thu, 22 Apr 2021 16:39:45 +1000 Subject: [Limdep Nlogit List] Fwd: Fwd: Question about Convolution test In-Reply-To: <3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de> References: <3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de> Message-ID: Hi Michael, Thank you so much for your help! It works wonderfully. But .. I have another question. How can I calculate the critical values for the Poe test? Are there a table of critical values available to compare the test statistics with? Your help is much appreciated! Best wishes, Thao ---------- Forwarded message --------- From: Danne, Michael Date: Thu, 22 Apr 2021 at 15:54 Subject: AW: [Limdep Nlogit List] Fwd: Question about Convolution test To: Limdep and Nlogit Mailing List Cc: Thao Thai Hi Thao, Run the model for the first subset with including the ;parameter command. Than you can copy/paste the individual WTPs in Excel. Do it in the same way with the second subset. In your Excel, each attribute is in a single column. Attribute 1 of subset one and attribute one of subset 2 should have different names in excel, for example car1 and car2. If you than use the poe test it is than CALC ; List ; Poe(car1,car2,1) $ You have to be careful which vector you list first in the command. As I remember the higher vector (higher mean) has to be the first. I don?t know if there is an easier way, but it should work. Best regards Michael -----Urspr?ngliche Nachricht----- Von: Limdep Im Auftrag von Thao Thai via Limdep Gesendet: Donnerstag, 22. April 2021 07:41 An: Limdep and Nlogit Mailing List Cc: Thao Thai Betreff: [Limdep Nlogit List] Fwd: Question about Convolution test Hi again, I found one relevant previous message with instructions on the Poe test below ( https://protect-au.mimecast.com/s/FNoMCoV1kpfrvZ33li1HGqD?domain=mailman.sydney.edu.au. However, I am still not sure how to test WTP estimates from WTP-space models for individual attributes from two datasets. I tried to replicate the suggested command as below: 1. I ran the first WTP-space model on one data subset and defined the vector of WTP estimates of 12 attributes: MATRIX ; vector1 = b (6:20)$ 2. I ran the second WTP-space using another data subset and defined the vector of WTP estimates (two data subsets have information on the same attributes) MATRIX ; vector2 = b (6:20)$ 3. I then ran the Poe test command as instructed. CALC ; List ; Poe(vector1,vector2,1) $ This command produced one single test statistic. However, I would like to have Poe test statistics for 12 individual attributes. Your suggestions would be appreciated. Please help! Best wishes, Thao "CALC ; List ; Poe(vector1,vector2) $ This produces the statistic based on the full convolution. Vectors must be defined with a MATRIX command. If x1 and x2 are two variables, use MATRIX ; vector1 = x1 ; vector2 = x2 $ then CALC Poe. The test can be based on the difference of the vectors if they are the same length. Use CALC ; List ; Poe(vector1,vector2,1) $ Regards Bill Greene" ---------- Forwarded message --------- From: Thao Thai Date: Wed, 21 Apr 2021 at 16:47 Subject: Question about Convolution test To: Limdep and Nlogit Mailing List Hi Nlogit user community, I would like to compare the WTP estimates from two WTP-space models (all random coefficients) using two different datasets. I am wondering what is the detailed procedure to conduct a Convolution test (Poe test) on the distributions of WTPs estimates in Nlogit? I could not find the procedure in the Manual, so any suggestions would be appreciated. Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for measuring the difference of empirical distributions. American Journal of Agricultural Economics, 87, 353?365. Thank you in advance. Best wishes, Thao _______________________________________________ Limdep site list Limdep at mailman.sydney.edu.au https://protect-au.mimecast.com/s/II58Cp81lrtnAK33QTDu1K4?domain=limdep.itls.usyd.edu.au From Thao.T.Thai at monash.edu Thu Apr 22 23:13:28 2021 From: Thao.T.Thai at monash.edu (Thao Thai) Date: Thu, 22 Apr 2021 23:13:28 +1000 Subject: [Limdep Nlogit List] Fwd: Question about Convolution test In-Reply-To: <3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de> References: <3e816556e4804fb8a0dbea06bff9678c@agr.uni-goettingen.de> Message-ID: Hi Nlogit users, Following Michael's instructions, I am able to generate Poe test statistics for individual attributes as below |-> CALC ;List; Poe(PRLH2,FRLH2,1) $ [CALC] = 264.1756004 |-> CALC ;List; Poe(PFL,FFL,1) $ [CALC] = 223.8058368 |-> CALC ;List; Poe(PCR1,FCR1,1) $ [CALC] = 1079.2828222 |-> CALC ;List; Poe(PCR2,FCR2,1) $ [CALC] = 135.7597390 |-> CALC ;List; Poe(PLO1,FLO1,1) $ [CALC] = 3489.5048159 |-> CALC ;List; Poe(PRLC1,FRLC1,1) $ [CALC] = 235.9289009 |-> CALC ;List; Poe(PRLC2,FRLC2,1) $ [CALC] = 522.8063550 Please let me know if these huge figures look sensible in nlogit and how to obtain p-values or level of significance for these figures? Please help or point me to the available instructions. Please help! Thank you in advance. Best regards, Thao On Thu, 22 Apr 2021 at 15:54, Danne, Michael < michael.danne at agr.uni-goettingen.de> wrote: > Hi Thao, > > Run the model for the first subset with including the ;parameter command. > Than you can copy/paste the individual WTPs in Excel. Do it in the same way > with the second subset. In your Excel, each attribute is in a single > column. Attribute 1 of subset one and attribute one of subset 2 should have > different names in excel, for example car1 and car2. If you than use the > poe test it is than CALC ; List ; Poe(car1,car2,1) $ > You have to be careful which vector you list first in the command. As I > remember the higher vector (higher mean) has to be the first. > > I don?t know if there is an easier way, but it should work. > > Best regards > Michael > > -----Urspr?ngliche Nachricht----- > Von: Limdep Im Auftrag von Thao > Thai via Limdep > Gesendet: Donnerstag, 22. April 2021 07:41 > An: Limdep and Nlogit Mailing List > Cc: Thao Thai > Betreff: [Limdep Nlogit List] Fwd: Question about Convolution test > > Hi again, > > I found one relevant previous message with instructions on the Poe test > below ( > https://protect-au.mimecast.com/s/8VIQC91WPRTk21ABziopbLO?domain=mailman.sydney.edu.au). > However, I am still not sure how to test WTP estimates from WTP-space > models for individual attributes from two datasets. > > I tried to replicate the suggested command as below: > 1. I ran the first WTP-space model on one data subset and defined the > vector of WTP estimates of 12 attributes: > MATRIX ; vector1 = b (6:20)$ > > 2. I ran the second WTP-space using another data subset and defined the > vector of WTP estimates (two data subsets have information on the same > attributes) > MATRIX ; vector2 = b (6:20)$ > > 3. I then ran the Poe test command as instructed. > CALC ; List ; Poe(vector1,vector2,1) $ > This command produced one single test statistic. However, I would like to > have Poe test statistics for 12 individual attributes. > > Your suggestions would be appreciated. Please help! > Best wishes, > Thao > > > "CALC ; List ; Poe(vector1,vector2) $ > This produces the statistic based on the full convolution. Vectors must be > defined with a MATRIX command. If x1 and x2 are two variables, use MATRIX > ; vector1 = x1 ; vector2 = x2 $ then CALC Poe. The test can be based on > the difference of the vectors if they are the same length. Use CALC ; List > ; Poe(vector1,vector2,1) $ Regards Bill Greene" > > > ---------- Forwarded message --------- > From: Thao Thai > Date: Wed, 21 Apr 2021 at 16:47 > Subject: Question about Convolution test > To: Limdep and Nlogit Mailing List > > > Hi Nlogit user community, > > I would like to compare the WTP estimates from two WTP-space models (all > random coefficients) using two different datasets. I am wondering what is > the detailed procedure to conduct a Convolution test (Poe test) on the > distributions of WTPs estimates in Nlogit? > > I could not find the procedure in the Manual, so any suggestions would be > appreciated. > > Poe test: Poe GL, Giraud KL, Loomis JB (2005). Computational methods for > measuring the difference of empirical distributions. American Journal of > Agricultural Economics, 87, 353?365. > > Thank you in advance. > Best wishes, > Thao > _______________________________________________ > Limdep site list > Limdep at mailman.sydney.edu.au > https://protect-au.mimecast.com/s/O2wyC0YKPviGm8Q3kfD00Yy?domain=limdep.itls.usyd.edu.au > > From Thao.T.Thai at monash.edu Mon Apr 26 15:20:54 2021 From: Thao.T.Thai at monash.edu (Thao Thai) Date: Mon, 26 Apr 2021 15:20:54 +1000 Subject: [Limdep Nlogit List] WTP- space model: Confidence interval of WTP distribution using Delta method Message-ID: Dear Nlogit users, Please help if you can! Your help is much appreciated! I ran a WTP-space model of which the results are below. Please help me clarify some of my confusions: (1) Is the confidence interval of the random parameters reported in the model output, for example of the HOS variable, the confidence interval of the mean WTP estimate for HOS variable? (2) Does that mean the WTP distribution for HOS variable depends on the *mean *WTP and its *standard error *(i.e. confidence interval of the mean WTP) and the *standard deviation* (i.e. the estimated coefficients and standard error for NsHOS) of the distribution for the WTP of HOS variables? Please help: (3) How can I compute the confidence intervals of WTPs distribution using Delta method? (4) How can I compute the confidence interval of the mean WTP using Delta method? Is it the confidence interval reported in the WTP-space model output? Suppose the Delta method Wald syntax is *Wald; Parameters = b; Covariance = varb* *;Labels = hos, pri, ind, gov, non, rlh1, rlh2, fl, cr1, cr2, lo1, sa, rlc1, rlc2, lo2, rlp1, rli1, rli2, rlg1, rln1;Fn1 = ? ;Fn2 = ?* *$* I got confused about what to put in the function to get confidence intervals of WTPs where the coefficients are already WTPs values? I really look forward to your answers! Thank you in advance! Best regards, Thao ----------------------------------------------------------------------------- Generalized Mixed (RP) Logit Model Dependent variable CHO Log likelihood function -6513.18857 Restricted log likelihood -12150.65191 Chi squared [ 39](P= .000) 11274.92669 Significance level .00000 McFadden Pseudo R-squared .4639639 Estimation based on N = 5530, K = 39 Inf.Cr.AIC = 13104.4 AIC/N = 2.370 --------------------------------------- Log likelihood R-sqrd R2Adj No coefficients ********** .4640 .4628 Constants only can be computed directly Use NLOGIT ;...;RHS=ONE$ At start values -7718.0848 .1561 .1543 Note: R-sqrd = 1 - logL/Logl(constants) Warning: Model does not contain a full set of ASCs. R-sqrd is problematic. Use model setup with ;RHS=one to get LogL0. --------------------------------------- Response data are given as ind. choices Replications for simulated probs. = 50 Used Halton sequences in simulations. RPL model with panel has 790 groups Fixed number of obsrvs./group= 7 BHHH estimator used for asymp. variance Number of obs.= 5530, skipped 0 obs --------+-------------------------------------------------------------------- | Standard Prob. 95% Confidence CHO| Coefficient Error z |z|>Z* Interval --------+-------------------------------------------------------------------- |Random parameters in utility functions.............................. HOS| 5.92660 8.03544 .74 .4608 -9.82257 21.67578 PRI| 30.0879*** 6.82100 4.41 .0000 16.7190 43.4568 IND| -74.2164*** 8.56240 -8.67 .0000 -90.9984 -57.4344 GOV| -1.41410 7.62304 -.19 .8528 -16.35499 13.52679 NON| -.55721 7.71549 -.07 .9424 -15.67928 14.56486 RLH1| -4.88831 9.96395 -.49 .6237 -24.41730 14.64068 RLH2| 15.4004** 7.46852 2.06 .0392 .7624 30.0385 FL| 15.1360*** 3.00154 5.04 .0000 9.2531 21.0189 CR1| 33.4554*** 3.29616 10.15 .0000 26.9950 39.9158 CR2| 17.2478*** 4.98946 3.46 .0005 7.4687 27.0270 LO1| -56.0650*** 3.79442 -14.78 .0000 -63.5019 -48.6280 SA| 1.0 .....(Fixed Parameter)..... RLC1| 11.6994 9.01142 1.30 .1942 -5.9627 29.3614 RLC2| 21.9054** 8.76364 2.50 .0124 4.7290 39.0818 LO2| -76.1803*** 5.08817 -14.97 .0000 -86.1529 -66.2077 RLP1| -21.7674*** 6.31574 -3.45 .0006 -34.1460 -9.3887 RLI1| 36.7621*** 9.08386 4.05 .0001 18.9581 54.5662 RLI2| 48.4521*** 6.98327 6.94 .0000 34.7651 62.1390 RLG1| -15.8780** 6.61678 -2.40 .0164 -28.8467 -2.9094 RLN1| -32.0373*** 8.21917 -3.90 .0001 -48.1465 -15.9280 |Distns. of RPs. Std.Devs or limits of triangular.................... NsHOS| 61.2749*** 5.69437 10.76 .0000 50.1141 72.4356 NsPRI| 52.0645*** 5.48074 9.50 .0000 41.3224 62.8065 NsIND| 81.7682*** 6.32951 12.92 .0000 69.3626 94.1738 NsGOV| 70.6895*** 5.40187 13.09 .0000 60.1021 81.2770 NsNON| 58.2880*** 6.73963 8.65 .0000 45.0786 71.4975 NsRLH1| 38.4853** 16.01183 2.40 .0162 7.1027 69.8679 NsRLH2| 15.0987 14.26854 1.06 .2900 -12.8671 43.0645 NsFL| 27.3007*** 5.52125 4.94 .0000 16.4792 38.1221 NsCR1| 1.25925 7.01920 .18 .8576 -12.49812 15.01662 NsCR2| 9.06253 9.13084 .99 .3209 -8.83358 26.95864 NsLO1| 58.1808*** 4.70198 12.37 .0000 48.9651 67.3965 CsSA| 0.0 .....(Fixed Parameter)..... NsRLC1| 61.6887*** 9.56351 6.45 .0000 42.9445 80.4328 NsRLC2| 8.02381 13.69708 .59 .5580 -18.82197 34.86959 NsLO2| 33.7236*** 7.81182 4.32 .0000 18.4128 49.0345 NsRLP1| 3.64345 12.20383 .30 .7653 -20.27562 27.56251 NsRLI1| 52.0114*** 13.12794 3.96 .0001 26.2811 77.7417 NsRLI2| 7.20127 13.87235 .52 .6037 -19.98804 34.39057 NsRLG1| 14.7726 11.03772 1.34 .1808 -6.8609 36.4061 NsRLN1| 51.6333*** 9.86131 5.24 .0000 32.3055 70.9611 |Variance parameter tau in GMX scale parameter....................... TauScale| 0.0 .....(Fixed Parameter)..... |Weighting parameter gamma in GMX model.............................. GammaMXL| 0.0 .....(Fixed Parameter)..... |Coefficient on SA in preference space form.................... Beta0WTP| .01539*** .00043 35.64 .0000 .01454 .01623 S_b0_WTP| 0.0 .....(Fixed Parameter)..... | Sample Mean Sample Std.Dev..................................... Sigma(i)| 1.0*** .1322D-05 ******** .0000 .10000D+01 .10000D+01 --------+-------------------------------------------------------------------- nnnnn.D-xx or D+xx => multiply by 10 to -xx or +xx. ***, **, * ==> Significance at 1%, 5%, 10% level. Fixed parameter ... is constrained to equal the value or had a nonpositive st.error because of an earlier problem. Model was estimated on Apr 23, 2021 at 08:10:02 PM -----------------------------------------------------------------------------